Notice that us are provided the massive of both reactants: this method we need to determine thelimiting reactant, i m sorry is the reactant that develops the less amount that product.

You are watching: Sodium bicarbonate and hcl balanced equation

This is due to the fact that once the limiting reactant is all used up, the reaction deserve to no longer proceed and also make an ext products.

This way the limiting reactant determines themaximum fixed of the product (CO2) formed.

We must perform amole-to-mole comparisonbetween every reactant and also CO2.

Balanced Reaction:NaHCO3(s) + HCl(aq)→NaCl(aq) + H2O(l) + CO2(g)

For NaHCO3:From the well balanced equation,1 mole that NaHCO3 kind 1 mole that CO2.

Themoles of CO2formed by8.67 gNaHCO3is:

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Problem Details

Sodium bicarbonate reacts with hydrochloric mountain in a gas-forming reaction to develop aqueous salt chloride, water, and carbon dioxide gas:

NaHCO3(s) + HCl(aq)→NaCl(aq) + H2O(l) + CO2(g)

Determine the massive of CO2 gas developed when 8.67 g the NaHCO3 is included to a systems that consists of 5.65 g of HCl.

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Frequently inquiry Questions

What scientific principle do you require to recognize in bespeak to settle this problem?

Our tutors have indicated that to deal with this problem you will require to apply the Limiting Reagent concept. You can view video lessons to find out Limiting Reagent. Or if girlfriend need much more Limiting Reagent practice, you can additionally practice Limiting Reagent exercise problems.

What professor is this trouble relevant for?

Based on our data, us think this difficulty is appropriate for Professor Blankenship's course at UGA.

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