Rewrite the square source of the division frac1625 together the division of square root fracsqrt16sqrt25. Take it the square source of both numerator and also denominator.

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George C. May 16, 2015displaystylesqrtfrac1125=fracsqrt11sqrt25=fracsqrt115 In generaldisplaystylesqrtab=sqrtasqrtb ...

displaystylefrac19 Explanation: displaystylefracsqrt1636=frac436=fraccancel4^1cancel36^9=frac19

displaystylefrac34 Explanation:First, simplify the portion inside the square root by separating bydisplaystyle2/2 . displaystylesqrtfrac1832=sqrtfrac916 ...

displaystylesqrt<3>frac1627=fracsqrt<3>163 Explanation: displaystyle16is not a cube. So the does not have a reasonable cube root.However,displaystyle27 ...

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displaystylefrac85 Explanation:We can adjust this problem to: displaystylesqrtfrac6425 ofracsqrt64sqrt25 ofrac85

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Rewrite the square source of the department frac1625 together the department of square roots fracsqrt16sqrt25. Take it the square root of both numerator and also denominator.

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