 ### Note the Pattern

The molar mass of any type of substance is its atomic mass, molecular mass, or formula mass in grams per mole.

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The regular table lists the atomic mass of carbon as 12.011 amu; the average molar mass of carbon—the mass of 6.022 × 1023 carbon atoms—is therefore 12.011 g/mol:

Substance (formula) Atomic, Molecular, or Formula Mass (amu) Molar Mass (g/mol)
carbon (C) 12.011 (atomic mass) 12.011
ethanol (C2H5OH) 46.069 (molecular mass) 46.069
calcium phosphate 310.177 (formula mass) 310.177

The molar mass of naturally arising carbon is different from that of carbon-12 and is not an integer because carbon occurs as a mixture of carbon-12, carbon-13, and carbon-14. One mole of carbon still has 6.022 × 1023 carbon atoms, however 98.89% of those atoms are carbon-12, 1.11% are carbon-13, and a map (around 1 atom in 1012) are carbon-14. (For even more information, view Section 1.6 ) Similarly, the molar mass of uranium is 238.03 g/mol, and also the molar mass of iodine is 126.90 g/mol. When we attend to elements such as iodine and also sulfur, which happen as a diatomic molecule (I2) and also a polyatomic molecule (S8), respectively, molar mass commonly describes the mass of 1 mol of atoms of the element—in this situation I and S, not to the mass of 1 mol of molecules of the facet (I2 and also S8).

The molar mass of ethanol is the mass of ethanol (C2H5OH) that has 6.022 × 1023 ethanol molecules. As you calculated in Example 1, the molecular mass of ethanol is 46.069 amu. Because 1 mol of ethanol has 2 mol of carbon atoms (2 × 12.011 g), 6 mol of hydrogen atoms (6 × 1.0079 g), and also 1 mol of oxygen atoms (1 × 15.9994 g), its molar mass is 46.069 g/mol. Similarly, the formula mass of calcium phosphate is 310.177 amu, so its molar mass is 310.177 g/mol. This is the mass of calcium phosphate that has 6.022 × 1023 formula devices.

The mole is the basis of quantitative historicsweetsballroom.comisattempt. It offers historicsweetsballroom.comists with a way to convert easily in between the mass of a substance and the variety of individual atoms, molecules, or formula systems of that substance. Conversely, it allows historicsweetsballroom.comists to calculate the mass of a substance required to acquire a desired number of atoms, molecules, or formula units. For example, to convert moles of a substance to mass, we use the relationship

( (moles)(molar ; mass) ightarrow mass ag1.71 )

or, more specifically,

( molesleft ( dfracgramsmole ight ) = grams )​

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### Example 1.7.2

For 35.00 g of ethylene glycol (HOCH2CH2OH), which is supplied in inks for ballsuggest pens, calculate the number of

moles. molecules.

Given: mass and molecular formula

Asked for: variety of moles and number of molecules

Strategy:

A Use the molecular formula of the compound to calculate its molecular mass in grams per mole.

B Convert from mass to moles by separating the mass given by the compound’s molar mass.

C Convert from moles to molecules by multiplying the number of moles by Avogadro’s number.

Solution:

A The molecular mass of ethylene glycol can be calculated from its molecular formula making use of the method illustrated in Example 1:

 2C (2 atoms)(12.011 amu/atom) = 24.022 amu 6H (6 atoms)(1.0079 amu/atom) = 6.0474 amu 2O (2 atoms)(15.9994 amu/atom) = 31.9988 amu C2H6O molecular mass of ethanol = 62.068 amu

The molar mass of ethylene glycol is 62.068 g/mol

B The number of moles of ethylene glycol present in 35.00 g can be calculated by dividing the mass (in grams) by the molar mass (in grams per mole):

( ; 35.00; g; ethylene glycolleft ( frac1; mol; ethylene; glycol; (g))62.068; g; ethylene; glycol est )=0.5639; mol; ethylene; glycol)

It is always a good idea to estimate the answer prior to you do the actual calculation. In this instance, the mass given (35.00 g) is less than the molar mass, so the answer should be less than 1 mol. The calculated answer (0.5639 mol) is indeed less than 1 mol, so we have actually most likely not made a significant error in the calculations.

C To calculate the number of molecules in the sample, we multiply the variety of moles by Avogadro’s number:

( molecules; of; ethylene; glycol=0.5639; molleft ( dfrac6.022 imes 10^231; mol ideal ) )

( = 3.396 imes 10^23; molecules​ )

Exercise

For 75.0 g of CCl3F (Freon-11), calculate the number of

moles. molecules.

0.546 mol 3.29 × 1023 molecules

### Example 1.7.3

Calculate the mass of 1.75 mol of each compound.

S2Cl2 (common name: sulhair monochloride; methodical name: disulfur dichloride) Ca(ClO)2 (calcium hypochlorite)

Given: variety of moles and also molecular or empirical formula

Strategy:

A Calculate the molecular mass of the compound in grams from its molecular formula (if covalent) or empirical formula (if ionic).

B Convert from moles to mass by multiplying the moles of the compound provided by its molar mass.

Solution:

We start by calculating the molecular mass of S2Cl2 and the formula mass of Ca(ClO)2.

A The molar mass of S2Cl2 is derived from its molecular mass as follows:

 2S (2 atoms)(32.065 amu/atom) = 64.130 amu 2Cl (2 atoms)(35.353 amu/atom) = 70.906 amu S2Cl​2 molecular mass of S2Cl​2 = 135.036 amu

The molar mass of S2Cl2 is 135.036 g/mol.

See more:

How Many Ounces Is A Sweet Potato, Cooked, Baked In Skin, Without Salt Amount

The mass of 1.75 mol of S2Cl2 is calculated as follows:

( moles; S_2Cl_2 left = mass; S_2Cl_2 )

( 1.75; mol; S_2Cl_2left ( dfrac135.036; g; S_2Cl_21;mol;S_2Cl_2 appropriate )=236;g; S_2Cl_2 )

B The formula mass of Ca(ClO)2 is obtained as follows:

 1Ca (1 atom )(40.078 amu/atom) = 40.078 amu 2Cl (2 atoms)(35.453 amu/atom) = 70.906 amu 2O (2 atoms)(15.9994 amu/atom) = 31.9988 amu Ca(ClO)2 formula mass of Ca(ClO)2 = 142.983 amu

The molar mass of Ca(ClO)2 is 142.983 g/mol

( moles; Caleft ( ClO ideal )_2left < dfracmolar; mass; Caleft ( ClO ideal )_21; mol; Caleft ( ClO ight )_2 ideal >=mass; Caleft ( ClO ideal )_2 )

( 1.75; mol; Caleft ( ClO ideal )_2left < dfrac142.983; g Caleft ( ClO ideal )_21; mol; Caleft ( ClO ight )_2 ideal >=250.; g; Caleft ( ClO ight )_2 )​

Exercise

Calculate the mass of 0.0122 mol of each compound.

Si3N4 (silsymbol nitride), offered as bearings and also rollers (CH3)3N (trimethylamine), a corrosion inhibitor