The ide used to solve this problem is based upon the Valence shell Electron Pair Repulsion theory.
The VSEPR theory is provided to predict the shape of the molecule v the help of variety of electrons pair bordering the central metal atom.
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By predicting the shape of molecule, bond have the right to be predicted.
For predicting the form of molecule by using VSEPR theory, it is important to attract Lewis framework of the molecule.
Lewis structure deserve to be drawn by count the total number of valence electron in the molecule. The rule for illustration Lewis structure room as follow.
First write the framework of the compound by place bonding atoms next to each other. The least electronegative atom rectal the central position.
Count the total number of valence electron in the molecule. Include the number of an adverse charge to the total variety of valence electrons and also subtract the number of positive charge from total number of valence electrons.
Complete the octets that the atoms bonded to central atom.
The atomic number of chlorine and also carbonare17 and6. The variety of valence electrons presentare 7 and 4 respectively. Yet there room 4chlorine atoms. So, total variety of valence electron in chlorine space 28. Thus, total variety of valence electrons space 32. These electrons are spread in together a method that every atom has complete octet.
The Lewis framework of CCl4\\rmCC\\rml_4CCl4 is attracted as follows:
Now, according to the VSEPR theory, the molecule with central atom external inspection to four electron groups has the tetrahedral shape. For tetrahedral shape, the shortcut angles between atoms space 109.5∘109.5^ \\circ 109.5∘ .
The atomic number of chlorine and also fluorine room 17 and 9. The number of valence electrons present in both atoms are 7. However there are 4 fluorine atoms. So, total number of valence electron in fluorine space 28. Also, over there is a negative charge. Thus, total number of valence electrons are 36. This electrons are dispersed in together a way that every atom has complete octet.
The Lewis structure of ClF4−\\rmClF_4^ - ClF4− is drawn as follows:
Now, according to the VSEPR theory, the molecule with central atom bonded to 6 electron teams has the square planar shape. For square planar shape, the bond angles in between atoms space 90∘90^ \\circ 90∘ .
The atomic variety of carbon and also oxygen are 6 and 8. The number of valence electrons present are 4 and 6 respectively.Also, there are two hydrogen atoms. Thus, total number of valence electrons space 12. This electrons are distributed in together a method that every atom has finish octet.
The Lewis framework of COH2\\rmCO\\rmH_2COH2 is drawn as follows:
Now, according to the VSEPR theory, the molecule with central atom external inspection to 3 electron groups has the trigonal planar shape. Because that trigonal planar shape, the bond angles in between atoms are 120∘120^ \\circ 120∘ .
The variety of valence electrons existing in iodine and also chlorine room 7 and 7 respectively. Yet there are two chlorine atoms. Thus, total number of valence electrons are 22. This electrons are spread in such a method that every atom has finish octet.
The Lewis framework of ICl2−\\rmICl_2^ - ICl2− is drawn as follows:
Now, according to the VSEPR theory, the molecule with main atom external inspection to 5 electron teams has the straight shape. For linear shape, the link angles between atoms room 180∘180^ \\circ 180∘ .Ans: part 1
The bond edge of CCl4\\rmCC\\rml_4CCl4 molecule is 109.5∘109.5^ \\circ 109.5∘ .Part 2
The bond edge of ClF4−\\rmClF_4^ - ClF4− molecule is 90∘90^ \\circ 90∘ .Part 3
The bond edge of COH2\\rmCO\\rmH_2COH2 molecule is 120∘120^ \\circ 120∘ .
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The bond edge of ICl2−\\rmICl_2^ - ICl2− molecule is 180∘180^ \\circ 180∘ .