How much energy is contained in 1 mol of each?a. X-ray photons with a wavelength of 0.135 nmb. g-ray photons with a wavelength of 2.15 * 10-5 nm

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his problem asks us to find the energy contained per one mole of photons with the following wavelength. So for letter, eh? We have zero point one five zero nano meters and we can convert that two meters by. There's one meter for every ten to the Ninth Nano meters, so we can convert that into one point five times ten to the minus tenth meters. Now we can find the energy of a single photons by equals H c. Over lambda the wavelength h is planks constant six point six two, six times ten to the minus thirty fourth C is the speed of light. So that's two point nine nine times ten to the eighth. And we divide that by our wavelength. We just found of one point five times ten to the minus tenth. And that gives us our energy perf otan to be one point three to six times ten to the minus fifteenth. So that's Jules, her photons. But we don't want jewels perform time. We want jewels. Prum. All. So to get Jules prom all we just multiply by avocados numbers six point two, two times ten to the twenty third. And that will give us our final answer of seven point nine eight times ten to the eighth and that's Jules per mall, which is what we want. Now we do the same thing for a letter B. We start with Ah, two point one five times ten to the minus fifth Nano meters and we convert that the same way. So one meter over ten to the ninth and Anna meters, not Nana meters cancel and we get our wavelength in meters two point one five times ten to the minus fourteenth meters and we use that same formula equals H C over Lambda the wavelength to determine the energy of a single photons. So six point six two six times ten to the minus thirty fourth times the speed of light two point nine, nine times ten to the eighth and we divide that by our wavelength to point one five times ten to the minus fourteenth.

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And that gives us our energy per photons to be nine point two, two times ten to the minus twelfth Jules Perf Otan. So again we multiply that by Abu God rose number six point two, two times ten to the twenty third and we get our final answer to be five point five five times ten to the twelfth Jules Permal, and that is our final answer.